x^2-8x+20=2

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Solution for x^2-8x+20=2 equation:


Simplifying
x2 + -8x + 20 = 2

Reorder the terms:
20 + -8x + x2 = 2

Solving
20 + -8x + x2 = 2

Solving for variable 'x'.

Reorder the terms:
20 + -2 + -8x + x2 = 2 + -2

Combine like terms: 20 + -2 = 18
18 + -8x + x2 = 2 + -2

Combine like terms: 2 + -2 = 0
18 + -8x + x2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-18' to each side of the equation.
18 + -8x + -18 + x2 = 0 + -18

Reorder the terms:
18 + -18 + -8x + x2 = 0 + -18

Combine like terms: 18 + -18 = 0
0 + -8x + x2 = 0 + -18
-8x + x2 = 0 + -18

Combine like terms: 0 + -18 = -18
-8x + x2 = -18

The x term is -8x.  Take half its coefficient (-4).
Square it (16) and add it to both sides.

Add '16' to each side of the equation.
-8x + 16 + x2 = -18 + 16

Reorder the terms:
16 + -8x + x2 = -18 + 16

Combine like terms: -18 + 16 = -2
16 + -8x + x2 = -2

Factor a perfect square on the left side:
(x + -4)(x + -4) = -2

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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